If a vector 2i^ +3j^+8k^ is perpendicular to the vector 4j^_4i^+xk^ then find the value of x
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Answer: let, vector a=2i^+3j^+8k^ and vector b=-4i^+4j^+xk^ here, vector a. vector b=0. (2i^+3j^+8k^)(-4i^+4j^+xk^) =0 -8+12+8x=0. 4+8x=0.
8x=-4
x=-4/8
x=-1/2
Explanation: When vectors are perpendicular then angle is 90 degree thus, in scaler product
vector a. vector b=|a||b|cos 90
=0
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