Physics, asked by rockydeepabhip8d0a7, 9 months ago

if a vector A is equal to ICAP + 2 J cap - 3 k cap is multiplied by 2 then magnitude of resultant vector will be

Answers

Answered by shiva0064
0

Answer:

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Answered by amitnrw
2

magnitude of resultant vector will be  = 2 √14   if A = i + 2j - 3k  multiplied by 2

Explanation:

vector A is equal to ICAP + 2 J cap - 3 k

A = i + 2j - 3k

| A |   = √1² + 2²  + (-3)²

=>  | A |  = √(1 + 4 + 9 )

=>  | A |  = √14

multiplied by 2 then magnitude of resultant vector will be  = 2 √14

Another method

A = i + 2j - 3k

=> 2A  = 2i + 4j - 6k

=> | 2A |   = √(2² + 4²  + (-6)²)

=>  | 2A |  = √(4 + 16 + 38)

=>  | 2A |  = √56

=>   | 2A |  = 2√14

magnitude of resultant vector will be  = 2 √14

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