if A vector + B vector + C vector= 0 and |A|= 4 , |B| = 3 and |C| = 5 then calculate the angle between B vector and C vector
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0
Answer:
calculate in your chapter 3
Answered by
2
Answer:
no answer
Explanation:
Given, a+b+c=0
and ∣a∣=5,∣b∣=3,∣c∣=7
⇒a+b=c
On squaring both sides, we get
(a+b)
2
=(−c)
2
⇒∣a+b∣
2
=∣c∣
2
⇒∣a∣
2
+∣b∣
2
+2a⋅b=∣c∣
2
(∵θ be the angle between a and b)
⇒(5)
2
+(3)
2
+2∣a∣∣b∣cosθ=(7)
2
⇒25+9+2⋅5⋅3cosθ=49
⇒30cosθ=15
⇒cosθ=
2
1
=cos60
∘
⇒θ=
3
π
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