If A vector × B vector is equal to B vector × A vector then find the angle between Avector and Bvector..
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A × B =B× A
according to farmula,,
(a+b)² =a²+ b²+ 2ab
(A×B)²= À²+B²+ 2A×B
(B×A)= B²+À²+2B× A
ABcosQ= Q = 1⁰
BAcos= Q=1⁰
take under root ,,
{ A+B}={B-A}
take under root ..
A²+B² +2ABcosQ =B²+A²-2BA
under root cancel each others
A²+B² +2ABcosQ = B²+A²-2BA
see the attachment
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