if a vector + b vector is equal to c vector and a square + b square is equal to c square then find angle the between them
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Formula used:
a→b→=abcosθ
Where the angle between two vectors a→ and b→ is θ .
Complete step by step answer:
The resultant vector of the two vectors a→ and b→ is c→ i.e a→+b→=c→………(1)
The modulus of the two vectors a→ and b→is a and b .
The sum of a and bis c i.e a+b=c…………(2)
By squaring both sides of eq. (1) we get,
(a→+b→)2=c2
⇒c2=(a→+b→)(a→+b→)
⇒c2=a2+b2+2a→.b→
Since a→.b→=abcosθ
⇒c2=a2+b2+2abcosθ
⇒c2=a2+b2+2abcosθ
⇒(a+b)2=a2+b2+2abcosθ fromtheeq.$(2)$
⇒a2+b2+2ab=a2+b2+2abcosθ
⇒cosθ=1
⇒θ=0∘
So, the angle between the vectors a→ and b→ is θ=0∘.
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