if a vector equals î - 3 j cap + 5 k cap and b vector equal to 2î - alpha j cap - k cap C vector equals to 2î + j cap - 2 k cap are coplanar then find the value of alpha
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Let,
a⃗ =2i^+2j^−2k^
b⃗ =5i^+yj^+k^
c⃗ =−i^+2j^+2k^
If a⃗ ,b⃗ ,c⃗ are coplanar, then their scalar triple product should be zero.
[a⃗ b⃗ c⃗ ]=0
That implies,
(a⃗ ×b⃗ ).c⃗ =0
By cyclic rotation,
(c⃗ ×a⃗ ).b⃗ =0
We have,
c⃗ ×a⃗ =6j^−6k^
Therefore,
(6j^−6k^).(5i^+yj^+k^)=0
6y−6=0
y=1
Explanation:
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