If a vector equals to 3 ICAP + 2 J cap and b vector is equals to two ICAP + 3 J cap - K cap and find a unit vector along a vector minus b vector
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11
Answer:
If we take vector A= 3i + 2j and the vector B = 2i + 3j -k so first we have to calculate the value of A+B which will be 5i + 5j -k and the value of A-B vector will be i-j+k.
Now to find A+B vector in -B dirrection we have to make dot product of A+B and A-B.
(A+B).(A-B) = 5 - 5 which will be equal to zero but the unit vector will be of the magnitude √(25+25) = √50 unit.
Answered by
5
Answer:
Step-by-step explanation:
root 50 is the ans
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