If A vector =i cap+2j cap+k cap,B vector =2 icap+2 kcap and C Vector=-2i cap+4k cap then magnitude of vector A+ Vector B- Vector C is
1)Root 20
2)Root 30
3)Root 65
4)Root 69
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Answer:
Given, a=2i+2j+3k,b=−1+2j+k and c=3i+j
We need to find value of a+tb⊥c
⇒(a+tb)⋅c=0
⇒a⋅c+tb⋅c=0
⇒t=−
b⋅c
a⋅c
⇒t=−
(−i+2j+k)⋅(3i+j)
(2i+2j+3k)⋅(3i+j)
⇒t=−
−3+2+0
6+2+0
=8
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