if a vector is 4i^+3j^ and B vector is 3i+4j then cosine of angle between a and a+b
Answers
Answered by
9
Answer:
I found:
θ
=
16.26
∘
Explanation:
between them:
→
v
⋅
→
w
=
∣
∣
→
v
∣
∣
∣
∣
→
w
∣
∣
cos
(
θ
)
=
v
x
w
x
+
v
y
w
y
Where you have that the scalar product is equal to the product of the modulii times the cosine of the angle between the vectors AND equal to the sum of the products between the components of the two vectors, or:
∣
∣
→
v
∣
∣
∣
∣
→
w
∣
∣
cos
(
θ
)
=
v
x
w
x
+
v
y
w
y
Now:
∣
∣
→
v
∣
∣
=
√
3
2
+
4
2
=
√
25
=
5
∣
∣
→
w
∣
∣
=
√
4
2
+
3
2
=
√
25
=
5
v
x
w
x
+
v
y
w
y
=
3
⋅
4
+
4
⋅
3
so:
5
⋅
5
⋅
cos
(
θ
)
=
3
⋅
4
+
4
⋅
3
25
cos
(
θ
)
=
24
θ
=
a
r
cos
(
24
25
)
=
16.26
∘.... thank for question
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