Question

If a vector is represented as 2î + 3j^ + 4k^ ,then magnitude of the vector is​

Answer 1

Answer:

The magnitude of the vector Ā = xî + yj^ + zk^

→A =√ x² + y² + z²

»»» Then the magnitude of the vector Ā = 2î + 3j^ + 4k^ is

→→→ A = √ 2² + 3² + 4²

→→→ A = √ 4 + 9 + 16

→→→ A = √29

Hope this helps you