Question

If a vector OP= 3i+3j is turned clockwise by angle of 15°,then y component of rotated vector would be

Answer 1

Vector OP is given as

$OP = 3i + 3j$

now we can find its magnitude as well as its direction both

$magnitude = \sqrt{3^2 + 3^2}$

$magnitude = 3\sqrt2$

now in order to find the direction

$\theta = tan^{-1}\frac{3}{3} = 45 degree$

now when vector is rotated by 15 degree

its magnitude will remain unchanged

while angle of vector will become 45 + 15 = 60 degree

now the Y component of the vector is given by

$Y = OP sin60$

$Y = 3\sqrt2 *sin60$

$Y = 3.67$

Answer 2

Answer:

hope this answer will help you