If a vehicle accelerates with the acceleration of 3.0m/s2 starting from rest. Then, how long will it take to go 3000 m ? find final velocity also
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Answer:-
Given:-
- Initial velocity (u) = 0 m/s [Rest]
- Acceleration (a) = 3 m/s²
- Distance travelled (s) = 3000 m or, 3 km.
To Find: Time it will take to reach 3 kilometres and it's final velocity,
OR: To find (t) and (v).
We know,
s = ut + ½at² and
v = u + at
where,
- s = Distance travelled,
- u = Initial velocity,
- t = Time taken,
- a = Acceleration and
- v = Final velocity.
Finding time taken:-
Here,
s = ½at²
3000 m = ½(3 m/s²)(t)²
→ 1.5 m/s² × t² = 3000 m
→ t² = (3000 m)/(1.5 m/s²)
→ t² = 2000 s²
→ t = √(2000 s²)
→ t = 10√(20) s
(→ t ≈ 44.7 s)
NOW, finding it's final velocity:-
Here,
v = at
→ v = (3 m/s²)[10√(20) s]
→ v = 30√(20) m/s
(→ v ≈ 134 m/s)
∴ Time it will take to cover 3 kilometers is approximately 45 seconds and the final velocity is about 134 m/s.
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