Question

If a vehicle is accelerated to 5 ms−2, how much time does it take to attain a velocity of 27

ms−1 which initially starts with 2ms−1?




please give me right ans

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Answer 1

Answer:

time =v-u\a

=27-2/2

=25/2

=12.5seconds

please ❤️❤️ to my answer

Answer 2

Answer:

5 seconds

Explanation:

As per the provided information in the given question, we have :

• Acceleration (a) = 5 m/s²
• Final velocity (v) = 27 m/s
• Initial velocity (v) = 2 m/s

We are asked to calculate time taken (t).

By using the first equation of motion,

$\longmapsto \bf{ v = u + at}$

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

$\longmapsto \rm{ 27 = 2 + 5t}$

$\longmapsto \rm{ 27 - 2= 5t}$

$\longmapsto \rm{ 25= 5t}$

$\longmapsto \rm{ \dfrac{25}{5} = t}$

$\longmapsto \bf{ 5s= t}$

∴ Time taken by it is 5 seconds.

$\rule{200}2$

More Information :

Whenever we are given u , v and a ; then we can find t by using any of the two formulae (simply by solving the linear equation) given below :

By using the first equation of motion :

$\longmapsto \rm{ v = u + at}$

By using the acceleration formula :

$\longmapsto \rm{a = \dfrac{v-u}{t} }$

Three equations of motion :

$\boxed{ \begin{array}{cc} \pmb{\sf{ \quad \: v = u + at \quad}} \\ \\ \pmb{\sf{ \quad \: s= ut + \cfrac{1}{2}a{t}^{2} \quad \: } } \\ \\ \pmb{\sf{ \quad \: {v}^{2} - {u}^{2} = 2as \quad \:}}\end{array}}$

Where,

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time
• s denotes distance