Question

If a vehicle is accelerated to 5 ms−2, how much time does it take to attain a velocity of 27

ms−1 which initially starts with 2ms−1?



right ans please


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Answer 1

Answer:

Time = 5 seconds

Explanation:

Acceleration of the vehicle is $\sf 5ms^{-2}$

We need to find the time in which the vehicle attains a velocity of $\sf 27ms^{-1}$ initially starts with $\sf 2ms^{-1}$

We know that,

First equation of motion :

⇒ v = u + at

Where,

• u(initial velocity) = $\sf 2ms^{-1}$
• v(final velocity) = $\sf 27ms^{-1}$
• a(acceleration) = $\sf 5ms^{-2}$

Substitute the values,

⇒ 27 = 2 + 5(t)

⇒ 27 = 2 + 5t

⇒ 27 - 2 = 5t

⇒ 25 = 5t

⇒ 25/5 = t

⇒ 5 = t

∴ The time taken is 5 seconds

_____________________

Note:

First equation of motion is v = u + at

Where,

• v = final velocity.
• u = initial velocity.
• a = acceleration.
• t = time.