English, asked by SanchitaSahoo, 5 hours ago

If a vehicle is accelerated to 5 ms−2, how much time does it take to attain a velocity of 27

ms−1 which initially starts with 2ms−1?



right ans please


Answers

Answered by ImperialGladiator
19

Answer:

Time = 5 seconds

Explanation:

Acceleration of the vehicle is \sf 5ms^{-2}

We need to find the time in which the vehicle attains a velocity of \sf 27ms^{-1} initially starts with \sf 2ms^{-1}

We know that,

First equation of motion :

⇒ v = u + at

Where,

  • u(initial velocity) = \sf 2ms^{-1}
  • v(final velocity) = \sf 27ms^{-1}
  • a(acceleration) = \sf 5ms^{-2}

Substitute the values,

⇒ 27 = 2 + 5(t)

⇒ 27 = 2 + 5t

⇒ 27 - 2 = 5t

⇒ 25 = 5t

⇒ 25/5 = t

⇒ 5 = t

The time taken is 5 seconds

_____________________

Note:

First equation of motion is v = u + at

Where,

  • v = final velocity.
  • u = initial velocity.
  • a = acceleration.
  • t = time.
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