if a velocity is given by the expression v=2t+3,find the force acting on particle mass 2kg
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1
Answer:
Given,
Velocity, v=(2t
i
^
+4
j
^
)
Change in velocity at time(t=2secandt=0), Δv=v
t=2
−v
t=0
=(4
i
^
+4
j
^
)−4
j
^
=4
i
^
.
Impulse, I=F.Δt=mΔv=2×4
i
^
=8
i
^
Hence, impulses is 8
i
^
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