Question

If a velocity of a train which starts from rest is 72km /h(20 m/s)after 5 minutes find out its acceleration and the distance travelled by the train in the time

Answer 1

Explanation:

v=u+at

u=0

20m/s=a*300seconds

a=1/15 m/s²

v²=2as

u=0

400=2/15*s

400*15/2=s

s=3000m.

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Answer 2

Answer:

v = 20 m/s

u = 0 m/s

t = 5 min = 5*60 =300 s

a = v - u/t

a = 20-0/300

a = 20/300

a = 1/15 m/s^2

S=ut+1/2at^2

s= 1/2*1/15*300*300

s= 3000 m