If a vertical pole of length 6m casts a shawdow 4m long on the ground and at the same time a tower casts a shawdow 28m long,then the height of the tower is?
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Answered by
0
it is a case direct proportion
let the tower's height be x
then
6/4 = x/28
x =28×6 /4
x =42 m
let the tower's height be x
then
6/4 = x/28
x =28×6 /4
x =42 m
Answered by
1
here is ur answer mate............
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