Math, asked by jairehshalom, 1 year ago

If A walks 7/4 km and jogs 3/5 km.Find the total distance covered by A. How much did A walk rather than jog?

Answers

Answered by ColinJacobus
5

Answer:  The total distance covered by A is \dfrac{47}{20}~\textup{km} and A walked \dfrac{23}{20}~\textup{km} rather than jogged.

Step-by-step explanation:  Given that A walks \dfrac{7}{4}~\textup{km} and jogs \dfrac{3}{5}~\textup{km}.

We are to find the total distance covered by A and the distance walked by A rather than jogged.

Let d and d' represents the distance walked by A and jogged by A respectively.

Then, according to the given information, we have

d=\dfrac{7}{4}~\textup{km},\\\\\\d'=\dfrac{3}{5}~\textup{km}.

Therefore, the total distance covered by A is given by

D=d+d'=\dfrac{7}{4}+\dfrac{3}{5}=\dfrac{35+12}{20}=\dfrac{47}{20}.

And, the distance walked by A rather than jogged is given by

D'=d-d'=\dfrac{7}{4}-\dfrac{3}{5}=\dfrac{35-12}{20}=\dfrac{23}{20}.

Thus, the total distance covered by A is \dfrac{47}{20}~\textup{km} and A walked \dfrac{23}{20}~\textup{km} rather than jogged.

Answered by empathictruro
1

Answer:

Distance covered= 47÷20 km

Step-by-step explanation:

Distance covered by walk = 7÷4 km

Distance covered by jog = 3÷5 km

Total distance = distance covered by walk+ distance covered by jog

                    = (7÷4) + (3÷5)

                  =( (7×5)+(3×4))÷20

                 =(35+12)÷20

                       = 47÷20

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