Question

If a weight of 65 kg is reduced to 60 kg , then find the percentage of reduction

Answer 1

SOLUTION:

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ANSWER:-

• Percentage of reduction = 7.672%

GIVEN:-

• Orignal weight = 65kg.
• weight after reduction = 60kg.

TO FIND:-

• Percentage of reduction.

SOLUTION:-

Let the percentage of reduction be x.

Reduced weight = 65kg - 60kg = 5kg.

FORMULA TO FIND PERCENTAGE OF REDUCTION:

$\rightarrow \sf \dfrac{reduced \: weight}{orignal \: weight} \times 100\%$

SOLVING BY APPLYING THE FORMULA:-

$\rightarrow \sf \dfrac{5kg}{65kg} \times 100\%$

$\rightarrow \sf \dfrac{5kg}{65kg} \times 100\%$

$\rightarrow \sf \dfrac{5kg}{65kg} \times 100\%$

$\rightarrow \sf \dfrac{1 kg}{13kg} \times 100\%$

$\rightarrow \sf \dfrac{1 \cancel{kg}}{13 \cancel{kg} } \times 100\%$

$\rightarrow \sf \dfrac{1 }{1} \times 7.672\%$

$\rightarrow \boxed{\sf \purple{{ 7.672\%}}}$

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Answer 2

Question:-

1. If a weight of 65 kg is reduced to 60 kg , then find the percentage of reduction.

Required answer:-

• 7.672% is the percent of reduction required

To find,

• Reduced percent

Given:-

• Original weight = 65 kg
• Reduced weight = 60 kg

Let,

• The percent of reduction be y

To find how much the man is reduced subtract 65 kg and 60 kg.

       = 65 kg - 60 kg

           = 5 kg

Formula to be used:-

$\rm\dfrac{reduced}{original} \times 100$

Solution:-

$\dfrac{5}{65} \times 100 \%$

$\dfrac{1}{13} \times 100 \%$

$\dfrac{1}{1} \times 100 \%$

$\bold\rm{Answer}=> {\fbox{7.672 \%}$

Therefore, the reduced percent is 7.672%