Question

If a wire conductor of resistance 0.4 Ω

is doubled in length, and cross-

sectional area of its base remains

same, its resistance becomes:

A. 0.1 Ω B. 0.2 Ω

C. 0.4 Ω D. 0.8 Ω

Answer 1

R is directly proportional to L.

So if u double the length of wire, the resistance will also double.

So resistance will be 2(0.4)  Ω = 0.8 Ω
Hope it helps:)