Question

if a wire has a resistance of 1.32 ohm,a length of 110 cm and an area of cross section 0.00415 cm2.find the specific resistance of the wire?​

Answer 1

Answer:

Given :-

• $If \: a \: wire \: has \: a \: resistance \: of \: 1.32ohm \: and \: a \: length \: of \: 110cm \: and \: area \: of \: cross \: section = 0.00415 {cm}^{2}$

□To prove :-

• Here we should find specific resistance of wire.

□Explanation :-

• $resistance \: of \: wire \: is \: given \: by \:$
• $R = \frac{pL}{a}$

• p denotes specific resistance.
• L is length of the wire.
• A denotes area of cross section .

• $1.32 = p \times \frac{110 \times {10}^{ - 2} }{415 \times {10}^{ - 5 } \times {10}^{ - 4} }$
• $1.32 = p \frac{110 \times {10}^{ - 2} }{415 \times {10}^{ - 9} }$
• $p = \frac{1.32 \times 415 \times {10}^{ - 9} }{110 \times {10}^{ - 2} }$
• $p = \frac{547.8 \times {10}^{ - 19} }{110 \times {10}^{ - 2} }$
• $p = 4.98 \times {10}^{ - 17} ohm \: m$

□Therefore ,

• Specific resistance of wire is 4.98×10^-17 ohm -m.

♧Hope it helps u mate .

♧Thank you .