If a wire having resistance (R) is stretched n times its original length . What will be its new resistance and resistivity
Answers
Answered by
14
Answer:
R' = n²R
Explanation:
When a wire is stretched n times the decrease in its area would become
LA = L'A' (volume remains the same)
⇒ LA = nL A'
∴ A' = A/n
R = rho L/A
R' = rho L'/A'
R/R' = L A' / L' A
= L (A/n) / (nL) A
= n⁻²
R' = n²R
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Answered by
2
Answer:
R' = n²R
Explanation:
When a wire is stretched n times the decrease in its area would become
LA = L'A' (volume remains the same)
⇒ LA = nL A'
∴ A' = A/n
R = rho L/A
R' = rho L'/A'
R/R' = L A' / L' A
= L (A/n) / (nL) A
= n⁻²
R' = n²R
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