Physics, asked by vijayant4938, 11 months ago

If a wire having resistance (R) is stretched n times its original length . What will be its new resistance and resistivity

Answers

Answered by Sreesha
14

Answer:

R' = n²R

Explanation:

When a wire is stretched n times the decrease in its area would become

 LA = L'A' (volume remains the same)

 ⇒ LA = nL A'

∴ A' = A/n

R = rho L/A

R' = rho L'/A'

R/R' = L A' / L' A

       = L (A/n) / (nL) A

       = n⁻²

R' = n²R

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Answered by laughoutloud42
2

Answer:

R' = n²R

Explanation:

When a wire is stretched n times the decrease in its area would become

 LA = L'A' (volume remains the same)

 ⇒ LA = nL A'

∴ A' = A/n

R = rho L/A

R' = rho L'/A'

R/R' = L A' / L' A

      = L (A/n) / (nL) A

      = n⁻²

R' = n²R

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