Question

If a wire is melted to form a wire of one third radius, what will be the ratio of the length of the wires?

Answer 1

Answer:

Let the length of the first wire be L and radius R

volume=πR^2L

Let the length of the second wire be l, and it's radius=R/3

πR^2L=π(R/3)^2.l

L=l/9

L/l=1/9