Question

if a wire of 100ohm is divided into 5 equal pieces and reformed into a new wire find the resistance ?​

Answer 1

Answer:

Each wire resistance = 100/5

= 20 ohm

Answer 2

Answer:

The resistance of the conductor is directly proportional to the length of the conductor.

$\implies R \propto L$

Cross sectional area will remain constant.

$\implies\dfrac{R_1}{R_2} = \dfrac{L_i}{L_f}$

$\implies\dfrac{100}{R_2} = \dfrac{L}{ \frac{L}{5} }$

$\implies\dfrac{100}{R_2} = \dfrac{5L}{ L }$

$\implies\dfrac{100}{R_2} = \dfrac{5}{ 1 }$

$\implies R_2 = \dfrac{100}{ 5 }$

$\implies \bf R_2 =20 \: \Omega$