Question

if a wire of length 36cm is bent in the form a semicircle ,what is the radius of the semi circle​

Answer 1

Answer:

➡️

$1 \div 2 \: \times \pi \times r \:circumference \: of \: circle$

➡️ ACCORDING TO QUESTION,

3.14*36

113.04

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Answer 2

Answer:

length of the wire =36cm

therefore,

perimeter of the wire =36cm

therefore,

perimeter of a semicircle = 1/2×2πr

= πr

πr = 36

$\frac{22}{7} \times r = 36$

$r = 36 \times \frac{7}{22}$

$r = 18 \times \frac{7}{11}$

$r = \frac{126}{11}$

$r = 11.4$

Step-by-step explanation:

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