if a wire of length 44cm is bent in the form of circle and again bent in form of rectangle of length12cm . then the area of circle and rectangle are in the ratio
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Answered by
2
Answer:
Given, Total length of the wire=44cm
∴ The circumference of the circle=2πr=44cm
⇒2×
7
22
×r=44
⇒r=
2×22
44×7
=7cm
Now, Area of the circle=πr
2
=
7
22
×7×7=154cm
2
Now the wire is converted into square,
Then perimeter of square=44cm
⇒4× side=44
⇒ side=
4
44
=11cm
Now, area of square=side×side=11×11=121cm
2
Therefore, on comparing the area of circle is greater than that of square, so the circle enclosed more area.
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Answered by
2
Answer:
given
total length of wire =44cm
therefore the circumference of circle=2πr=44 cm
2×22/7×r=44
r=44×7/2×22
=7cm
now area of circle=πrsquare
=22×7×7=154cm square
now the wire is converted into square the perimeter of square=44cm
4×side=44
side=44/4=11cm
now area of square=side×side=11×11 =121cm square
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