Question

If a wire of resistance 1Ω is stretched to double of its length, then the resistance will become
(Α) 1/2Ω
(Β) 2Ω
(C) 4 Ω
(D) 4Ω​

Answer 1

Answer:

option c is answer

Explanation:

if x²+y²+z²=2(x-y-z)-3 find the value of 2x-3y+4z

Answer 2

Answer:

given that

resistance of wire = 1Ω

so ,

we know that

R= ₱l/a

here ₱ is the resistivity

so ,,new length= 2l

hence area of cross section is half

a= a/2

now

R'= ₱ 2l/a/2

R'= 4 ₱ l/a

so , R'= 4R