If a wire of resistance 1 ohm is stretched to double it's lenght then the resistance will become please answer me the perfect answer
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1
Answer:
4ohm
Explanation:
The point here to understand is when we stretch a wire we increase is its length and as the volume of the wire is kept constant, so the area of the cross-section of the wire has to be now exactly half of the initial value.
Now let us say the original length of wire is '1',the area of cross-section of the wire is 'A' and the resistivity of the wire is 'P', then acc. to the formula for resistance
R=P*(I/A)
Now after stretching the wire,
Length=2*l Area=A/2
So the new resistance
R'=P*[21/(A/2)]
R'=4*[P*(I/A)]
R'=4R
So the new resistance is 4 times the initial resistance.
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