Question

If a wire of resistance r is divided into 8 parts and they are connected in parallel net resistance?

Answer 1

R=

$r = \frac{8}{r} + \frac{8}{r} + \frac{8}{r} + \frac{8}{r} + \frac{8}{r} + \frac{8}{r} + \frac{8}{r} + \frac{8}{r} \:$

$new \: r = \frac{8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 }{r}$

r' = 64÷r

Net resistance will be 1:64

Hope itbhelps