If a wire of resistance r is melted and recast to half its length, the new resistance of the wire will be
Answers
Answered by
36
Answer:
R/4
Explanation:
original resistance = R = p*L/A
After recasting :
length = L/2
Area = 2A
New resistance R' = p*L/4A
R'/R = p*L/A
p*L/4A
=> R' = R/4 [ANS]
Similar questions