if a wire of resistance R is melted and recast to half of its length then the new resistance would be
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Explanation:
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As resistance is directly proportional to length and inversely proportional to cross sectional area, hence resistance will become one fourth of the original.
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Initially ,
R =pL/A
here,
R=resistance
p=resistivity
L=length
A =area of cross section
Now ,
On melting new length becomes half of it's initial length
L' =L/2
So the area of cross section doubles
A '= 2A
R ' = p L/4A
R '= R/ 4
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