If a wire of resistance "R" is stretched 'n' times its new resistance is "R1" . If it is compressed 'n' times its new resistance is "R2". Find the ration R2/R1.
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Explanation:
Correct option is
C
4 : 1
As we know that, R
1
=ρ
a
l
=ρ
V
l
2
,
where l= length of wire, a= area of cross-section of the wire and V= volume of the wire.
So, R
1
∝l
2
⇒
R
2
R
1
=(
l
2
l
1
)
2
=(
2
1
)
2
⇒R
2
:R
1
=4:1
Hope it is helpful
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