If a woman age today is seven year less than three-fourths of her age twenty years from now
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Answer:
a woman's age today is seven years less than three Fourths of her age twenty years From now, how old is she today?
Answer:
She is 32 years old today.
Solution:
\begin{gathered}x = \frac{3}{4} (x + 20) - 7 \\ x = \frac{3}{4} \: x + \frac{3}{4} x20 - 7 \\ x - \frac{3}{4} x = 15 - 7 \\ \frac{1}{4} x = 8 \\ \\ x = 4 \times 8 = 32 \\ \\ \\ so \: she \: is \: 32years \: \: old \: today\end{gathered}
x=
4
3
(x+20)−7
x=
4
3
x+
4
3
x20−7
x−
4
3
x=15−7
4
1
x=8
x=4×8=32
sosheis32yearsoldtoday
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