Math, asked by zainabsange3, 4 months ago

If a wooden box of dimensions 8 m x 7 m x 6 m is to carry boxes of dimensions 4
cm x 3cm x 2 cm, then find the maximum number of boxes that can be carried in
the wooden box. Also find the surface area of the boxes.

Answers

Answered by laasyaasree8281
4

Step-by-step explanation:

big box volume = 8×7×6 = 336m³

small box volume = 4×3×2 = 24m³

no.of boxes = 336/24 = 14 small boxes can be fixed in the big box

surface area of big box = 2[(8×7)+(7×6)+(8×6)] = 2(56+42+48) = 292m²

surface area of small box = 2[(4×3)+(3×2)+(2×1)] = 2(12+6+2) = 40m²

Answered by ranjeetkumar372009
2

8m=800cm

7m=700cm

6m=600cm

carried=800×700×600/4×3×2=14000000ANS

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