if a work is done by 12 man and 15 women in 21 days then in how many day the work will done by 6 man and 10 women?
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Answer:
18 days
The work can be finished by 12 men in 21 days. The work can be finished by 15 women in 21 days. Therefore 18 days are required to finish the work by 6 men and 10 women, when work together.
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Step-by-step explanation:
18 days required to complete same work by 6 men and 10 women.
Given: 12 men or 15 women can complete work in 21 days
To find: Days it takes to complete same work by 6 men and 10 women
Solution:
12 men = 15 women ⇒ 1 man
Men = \frac{15}{12}1215 women
Men = \frac{5}{4}45
15 women can finish the work by 21 days
6 men = 6 \times \frac{5}{4}6×45 women
6 men = \frac{15}{2}215
6 men and 10 women = \frac{15}{2}+10215+10 =\frac{35}{2}235
\frac{35}{2}235 women can finish the work= 21 \times 15 \times \frac{2}{35}21×15×352 = 18 days.
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