if a worker is given 960 for 12 days how much is he given in 10 days
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given: worker is given 960 for 12 days
960÷12
80
so we know that worker is given 80 for 1 day
therefore gor 10 days
10×80
800
Answered by
63
Work done by A in 1 day =1/9
Work done by B in 1 day = 1/18
Work done by B in last 3 days = 1/18×3= 1/6
Remaining work=1−1/6= 5/6
Work done by A and B in 1 day = 1/9+ 1/18= 3/18= 1/6
Hence no. of days in which A and B worked together is =5/6|1/6 =5 days
Then total time to complete the work =3+5=8 days.
Same like this process you have to do
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