Question

if a^x-1=b^y-1 then
find the
value of (x,y)​

Answer 1

Step-by-step explanation:

We have,

a

x−1

=bc

a

a

x

=abc

a

x

=abc

a=(abc)

1/x

…(1)

Similarly,

b=(abc)

1/y

…(2)

c=(abc)

1/z

…(3)

Multiply (1),(2),(3)

abc=(abc)

1/x

.(abc)

1/y

.(abc)

1/z

abc=(abc)

1/x+1/y+1/z

∴

x

1

+

y

1

+

z

1

=1

xyz

xy+yz+zx

=1

xy+yz+zx=xyz

xy+yz+zx−xyz=0