Math, asked by mpranathi250, 6 months ago

if a^x-1 =b^y+1 then find value of (x,y)

Answers

Answered by ladenmolla1804

1

Answer:

x/y=2

Step-by-step explanation:

a^x-b^y=2

a^x/b^y=2(log rules)

loga^a^x=2logb^b^y(loge=loga catch)

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