if a x^2 + bx + c = zero has only one solution. prove that a ^2 =4 b
Answers
Answered by
0
Answer:
If one roots is zero, then product of roots is zero and sum is not zero.
⇒
a
c
=0;−
a
b
=0
⇒c=0;b
=0.
Answered by
1
Answer:
the answer is 16
Step-by-step explanation:
B square -4ac
(-4)square-4×1×0
16-0=
16
16>0
b^2-4ac>0
it has two distinct real roots
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