If A = { x: 2x + į , XEN, X <5}
B= {x? scis a composite no; x = 12}
Then show that (AUB)- (ANB) = (A-3) U(B-A)
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Step-by-step explanation:
Answer:
Given,
A={x : 2x+1, x ∈ N, x ≤ 5 },
B={x : x is a composite number, x ≤ 12 },
Since, composite number is a positive integer which is not prime,
Thus, the roster form of the sets are,
A = {3, 5, 7, 9, 11 }
B = { 4, 6, 8, 9, 10, 12 },
A ∪ B = all elements of A and B = { 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 }
A ∩ B = common elements of A and B = { 9 },
(A ∪ B) - (A ∩ B) = { 3, 4, 5, 6, 7, 8, 10, 11, 12 },
A - B = { 3, 5, 7, 11 },
B - A = { 4, 6, 8, 10, 12 },
( A - B ) ∪ ( B - A ) = { 3, 4, 5, 6, 7, 8, 10, 11, 12 },
⇒ (A ∪ B) - (A ∩ B) = ( A - B ) ∪ ( B - A )
Hence, proved.....
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