Math, asked by shankar71, 10 months ago

if A=(x,-7),B=(2,5) and AB=13 units find 'x'​

Answers

Answered by nhorsanglama
14

Answer:

hope you get it

Step-by-step explanation:

here, let x1=x,y1=-7,x2=2,y2=5

we know that

distance (AB)or(d)=√(x2-x1)²+(y2-y1)²

13=√(2-x)²+(5+7)²

13=√4-4x+x²+144

13=√x²-4x+148

squaring on both side

169=x²-4x+148

x²-4x-21=0

x²-7x+3x-21=0

x(x-7)+3(x-7)=0

(x-7)(x+3)=0

Therefore,

x=7 or -3

answer

Answered by neeladharkamath
4

Answer:

Step-by-step explanation:

given

A=(x,-7) = (x1,y1)

B= (2,5) = (x2,y2)

Using distance formulae,

AB =  The whole root of (x2-x1)the whole square +(y2-y1)the whole square

substituting the values,

13=The whole root of (2-x)the whole square +  (5-(-7))the whole square

13=The whole root of (4+x2-4x)  +  (144)

169=  4 +x2 - 4x +144

169-144-4= x2-4x

21 = X2 - 4X

0= X2-4X -21

0=X2 -7X+3X -21

0= X(X-7) + 3(X-7)

0= (X-7) (X+3)

X-7=0 OR X+3=0

THEREFORE X=7 OR X=-3

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