if A x A has 16 elements, S = {(a, b) EAxA:a< b}; (-1, 2) and (0, 1) are two
elements of S, then find the remaining elements of S.
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Answer:
Total number of elements in the set S = (-1,0), (-1,1), (-1,2), (0,1), (0,2), (1,2)
Remaining element of S other than (-1,2) and (0,1) are = (-1,0), (-1,1), (0,2), (1,2)
Step-by-step explanation:
S={(a, b) belong to AXA :a<b}
S is a set in which the elements are denoted as (a,b) where
1. a is less than b and
2. (a,b) belongs to AXA
Note: There are only 6 elements in AXA satisfies the above conditions.
Step-by-step explanation:
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