If A=(x-a) (x-b) (x-c)...(x-z). Then number of terms in the expansion of (a+A) (b+A)
5. if A = (x-a) (x-b) (x-c) ........
(c+A) ..........(z+A) is
(1) 1
(2) 27
(3) 56
(4) 43
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A = (x - a)(x - b)(x - c) .........(x - z)
In the RHS, there is one factor x - x = 0
=> A = 0
Hence, a + A = a + 0 = 0
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