Question

If a^x=b^3, b^y=c^3, c^z=a^3,
then the value of xyz will be​

Answer 1

${\fbox{\fbox{\huge{\bold{\large{ANSWER}}}}}$

$given,\\a^x=b^3\\b^y=c^3\\c^z=a^3$

so,

$a^{xy}=b^{(y)3}$

$a^{xy} = c^{(3)3} =c^9$

$a^{xyz} = c^{(z)9}$

$a^{xyz} = a^{(3)9}$

$a^{xyz} = a^{27}$

now since bases are equal, we can equate the exponents.

therefore,

xyz = 27

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