Question

If a^x=b^y=c^z and abc=1, then let us show that xy+yz+zx=0​

Answer 1

Step-by-step explanation:

a^x=b^y=c^z

abc=1

a°=1

a power 0 is 1

any number that has power zero then it's value is 1

In the same way we can say that x=0,y=0 and z=0

so, (a^0)(b^0)(c^0)=(1)(1)(1)=1

x=0 y=0 z=0

xy+yz+xz= (0)(0)+(0)(0)+(0)(0)

== 0+0+0= 0

xy+yz+xz=0

Hence proved

hope this helps you