Question

If a^x=c^q=b and c^y=a^z=do then prove that xy=qz

Answer 1

hence the expression is proved

Answer 2

Hi ,

a^x = c^q

a = c ^(q/x ) ---( 1 )

c^y = a^z

= [ c^(q/x ) ]^z [ from ( 1 ) ]

c^y = c^( qz/x )

[ since ( a^m ) ^n = a^mn ]

y = qz/x

[ since If a^m = a^n then m = n ]

xy = qz

Hence proved.

I hope this helps you.

:)