Question

If a(x) = loge sinx and B(x) = loge cos x, then find the value of e^a(x) +e^B(x)

Answer 1

Answer:

answer is 2.

Step-by-step explanation:

e^logesinx + e^logecosx

= (e^loge)^sinx + (e^loge)^cosx { a^mn = (a^m)^n }

= (1)^sinx + (1)^cosx { a^loga = 1 }

= 1 + 1 = 2