Question

If a = x + square root x^2 +1, then x =
pls answer it fast . Step by step explanation needed( process )​

Answer 1

Answer:

$\frac{1}{2a} (a^{2} - 1)$

Step-by-step explanation:

a = $x + \sqrt{x^{2} + 1}$

=>a - x = $\sqrt{(x^{2} + 1)}$

=> $a^{2} - 2.a.x + x^{2} = x^{2} + 1$

=> -2ax = -$(a^{2} - 1)$

=> x = $\frac{1}{2a} (a^{2} - 1)$