Question

IF A={x:x^2-16=0,x belongs to R}and B={x:x^2-5x+6=0

Answer 1

Step-by-step explanation:

A={x:

xis a natural number}=

{1,2,3,4,5.....}

B=

{x:

x is an even natural number}=

{2,4,6,8.....}

C=

{x:

x is an odd natural number}=

{1,3,5,7,9.......}

D=

{x:

xis a prime number}=

{2,3,5,7....}

(i)

A∩

B=

{x:

x is a even natural number}=

B

(ii)

A∩

C=

{x:

x is an odd natural number}=

C

(iii)

A∩

D=

{x:

x is a prime number}=

D

(iv)

B∩

C=

ϕ

(v)

B∩

D=

{2}

(vi)

C∩

D=

{x:

xis odd prime number}

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