Math, asked by ibrahimibbu0747, 5 months ago

if A =(x/x^2-3x2=0) find a​

Answers

Answered by ishigoel02
1

Answer:

A={2,1}

Step-by-step explanation:

the set A belongs to those values of x for which

x²-3x+2=0. This implies that Set A contains roots of the equation.

therefore,

x²-2x-x+2=0

x(x-2)-1(x-2)=0

(x-1)(x-2)=0

Either x-1=0 or x-2=0

x=1 or x=2

Hope this helps you

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