if A =(x/x^2-3x2=0) find a
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Answer:
A={2,1}
Step-by-step explanation:
the set A belongs to those values of x for which
x²-3x+2=0. This implies that Set A contains roots of the equation.
therefore,
x²-2x-x+2=0
x(x-2)-1(x-2)=0
(x-1)(x-2)=0
Either x-1=0 or x-2=0
x=1 or x=2
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